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X2-(2b-1)x+(b2-b-20)=0 find the value of x

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X2-(2b-1)x+(b2-b-20)=0 find the value of x

Posted by Sakshi Bachles 5 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 5 years, 11 months ago

In the given quadratic equation, x² - (2b - 1 ) x + (b²- b - 20) = 0

A= +1, B= - (2b - 1 ), C= (b²- b - 20)

$x = {-B \pm \sqrt{B^2-4AC} \over 2A}$

$x = \frac { ( 2 b - 1 ) \pm \sqrt { ( 2 b - 1 ) ^ { 2 } - 4 \left( b ^ { 2 } - b - 20 \right) } } { 2 }$
$x = \frac { ( 2 b - 1 ) \pm 9 } { 2 }$
$x = \frac { 2 b + 8 } { 2 } \quad and \quad x = \frac { 2 b - 10 } { 2 }$

$\therefore x= b+4 \quad and \quad x=b-5$

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CBSE > Class 10 > Mathematics