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27.6g of K2CO3 was created by …

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27.6g of K2CO3 was created by a series of reagents so as to convert all Carbon to K2Zn3[Fe(CN)6] Calculate the weight of product formed

    • Posted by Manish Rao 8 years, 3 months ago

    CBSE > Class 12 > Chemistry
    • 1 answers

    Gurvinder Kaur 7 years, 10 months ago

    99 gm of K2CO3 gives 485.98 gm of K2Zn3(Fe(CN)6)
    So, 27.6 gm of K2CO3 will give 485.98X27.6/99=135.46 gm of K2Zn3(Fe(CN)6)

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