If sec theta is equal to …
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Sia ? 5 years, 11 months ago
By the given condition of question
secθ=x+14x
∴tan2θ=sec2θ−1
⇒tan2θ=(x+14x)2−1=x2+116x2+12−1=x2+116x2−12=(x−14x)2
⇒tanθ=±(x−14x)
⇒tanθ=(x−14x) or, tanθ=−(x−14x)
CASE 1: When tanθ=−(x−14x): In this case,
secθ+tanθ=x+14x+x−14x=2x
CASE 2: When θ=−(x−14x): In this case,
secθ+tanθ=(x+14x)−(x−14x)=24x=12x
Hence, secθ+tanθ=2x or ,12x
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