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A gaseous hydrocarbon gives upon combustion …

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A gaseous hydrocarbon gives upon combustion , 0.72g of water and 3.08g of CO2. What is the empirical formula of the hydrocarbon?
  • 1 answers

Dr. Kamlapati Bhatt 7 years, 9 months ago

Since , the hydrocarbon on complete combustion gives out  given weights CO2  &   H2O  

Let the weight of hydrocarbon which on combustion gives out  COand HO  be =  x g

then ,

Step 1 .  /

calculate percentage of H   &   C   present in the hydrocarbon ,  separately

Step 2 /  calculate the number of atoms  of  C  and H  from the % as =   % of element /  atomic mass of element

Step 3 /     Calculate the whole number ratio of C : H in the hydrcarbon

Step 4 /   Infer the empirical formula of the hydrocarbon 

Calculations for Step 1 to 4  are tabulated as below :  

No. combustion products Given weights weights of... percentage of .... No.of moles whole number ratio
1 CO2 3.08 g

C= 1244X3.08

= 0.84 g

C  =  0.84xX100

84x/ 12

7x

 
2. H2 O 0.72 g

H =218X0.72

=  o.08 g

H=0.08xX100

8x/ 1

8x

= 8/x

 
           

C: H = 7 :  8 

 

Since empirical formula represents  the simplest whole number ratio of various  present in a compound ,

 The empirical formula of the hydrocarbon is  C7 H8

 

 

 

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