A gaseous hydrocarbon gives upon combustion …
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Dr. Kamlapati Bhatt 8 years, 4 months ago
Since , the hydrocarbon on complete combustion gives out given weights CO2 & H2O
Let the weight of hydrocarbon which on combustion gives out CO2 and H2 O be = x g
then ,
Step 1 . /
calculate percentage of H & C present in the hydrocarbon , separately
Step 2 / calculate the number of atoms of C and H from the % as = % of element / atomic mass of element
Step 3 / Calculate the whole number ratio of C : H in the hydrcarbon
Step 4 / Infer the empirical formula of the hydrocarbon
Calculations for Step 1 to 4 are tabulated as below :
C= {tex}\frac{12}{44} X 3.08{/tex}
= 0.84 g
= {tex}\frac{84}{x}{/tex}/ 12
= {tex}\frac{7}{x}{/tex}
H ={tex}\frac{2}{18} X 0.72{/tex}
= o.08 g
{tex}\frac{8}{x}{/tex}/ 1
= {tex}\frac{8}{x}{/tex}
= 8/x
C: H = 7 : 8
Since empirical formula represents the simplest whole number ratio of various present in a compound ,
{tex}\therefore{/tex}The empirical formula of the hydrocarbon is C7 H8
1Thank You