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a particle having initial velocity 5 …

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a particle having initial velocity 5 m/s moves with a constant acceleration 2 m/s² for a time 10 seconds along a straight line find the displacement of the particle in tha last one second and the total distance travelled in the 10 seconds

    • Posted by Gaurav Mahor 8 years, 3 months ago

    CBSE > Class 11 > Physics
    • 1 answers

    Sakshi Dahiya 8 years, 3 months ago

    Total distance=s =ut+1/2at^2 where u=5m/s a=2m/s^2 & t=10s S10th=u+a/2(2*n -1) where a=2 m/s^2 n=10s (1) V at 9th sec. =u at 10th sec. v= u + at where u=5 a=2 &t=9 This v is initial velocity of 10th sec. and can be put into (1) eq. Hence ,Snth can be calculated

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