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Derive the expression for electrical conductivity …

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Derive the expression for electrical conductivity of a material in terms of relaxation time 

    • Posted by Benita Benoy 7 years, 11 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Sudhanshu Saumya 7 years, 11 months ago

    v = I/neA, v = eEt/m where v is drift velocity, I is current inside the conductor, n is no. of electrons per unit volume, e is electronic charge present on the electron, A is area of cross section, E is electric field applied across the conductor, t is the relaxation time, m is the mass of electron. I/neA = etE/m, I/A = (ne2(square)t/m)E, I/A = αE where α is ne2(square)t/m I/A = αV/L where V is potential difference and L is the length of conductor. V = LI/Aα, V = (1/α)(LI/A) V = RI which is ohms law, We can see that 1/α acts as resistivity of the conductor, hence α will be conductivity Conductivity of a material = ne2(square)t/m where t is relaxation time.

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