Treatment of alkyl halides with KOH …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Dinesh Kumar 8 years, 4 months ago
- 1 answers
Test
Related Questions
Posted by Prity Rani Mishra 1 year, 6 months ago
- 0 answers
Posted by Karan Kumar Mohanta 1 year, 5 months ago
- 1 answers
Posted by Bhavishaya 2009 1 year, 6 months ago
- 0 answers
Posted by Kashish Baisla 9 months, 3 weeks ago
- 1 answers
Posted by Roshni Gupta 1 year, 6 months ago
- 0 answers
Posted by Priya Dharshini B 1 year, 5 months ago
- 4 answers
Posted by Shikhar Manav 1 year, 6 months ago
- 0 answers
Posted by Mahi Sharma 1 year, 6 months ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Dr. Kamlapati Bhatt 8 years, 4 months ago
The treatment of alkyl halide with aqueous KOH solution leads to the formation of alcohols because -
Aqueous KOH ionises to form hydroxyl ions ( OH- ) . Since OH- ion is a strong nucleophile it brings about substitution reaction with alkyl halides forming alcohols.
KOH (aq) --------------> K+ (aq) + OH- (aq)
RCl + OH - (aq) ------------> R-OH + Cl- (aq)
but with alcoholic KOH solution ,an alkene is formed .
This is due to formation of an alkoxide ion (RO- ) . The alkoxide ions are much stronger bases than OH- ions and eliminates a molecule of HCl from alkyl halide to form alkenes
C2 H5 Cl + KOH (alcoholic) ------------> CH2 = CH2 + KCl + H2O
1Thank You