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A rectangle having sides x+3y,7,13,3x+y.Find the …

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A rectangle having sides x+3y,7,13,3x+y.Find the value of x and y.

Posted by Gaurav Tamta 7 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Chanchal Garg 7 years, 10 months ago

We know Opposite sides of a rectangle are equal So, x+3y=13.......(1) 3x+y=7.............(2) By elimination method Equation (1) multiply by 3 So , 3x+9y=39 3x+ y=7 (on subtraction) We give, y=4 Now ,put the value of y in equation (1) X+3y =13 X+3(4)= 13 X=13-12 X=1

0Thank You

Chanchal Garg 7 years, 10 months ago

Y=1 and x=4

1Thank You

ANSWER

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