Find the area of an isocelas …
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Posted by Micro Max Chamoli 7 years, 10 months ago
- 1 answers
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Rashmi Bajpayee 7 years, 10 months ago
s = a+a+b2=2a+b2
Now, Area of triangle = √s(s−a)(s−b)(s−c)
= √2a+b2(2a+b2−a)(2a+b2−a)(2a+b2−b)
= √2a+b2(2a+b−2a2)(2a+b−2a2)(2a+b−2b2)
= √2a+b2(b2)(b2)(2a−b2)
= √4a2−b24(b2)2
= b4√4a2−b2
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