if cosecA + cotA =p then …
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Posted by Anurag Sahu 5 years, 11 months ago
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Sia ? 5 years, 11 months ago
Given, cosec θ + cot θ = p...(i)
We know that, cosec2θ−cot2θ=1
⇒(cosecθ+cotθ)(cosecθ−cotθ)=1
⇒p(cosecθ−cotθ)=1
⇒cosecθ−cotθ=1p ....(ii)
Adding i and ii, we get
2cosecθ=p+1p
cosecθ=p2+12p
⇒sinθ=1cosecθ=2pp2+1
We know that,cosθ=√1−sin2θ=√1−4p2(p2+1)2=√p4+1−2p2(p2+1)2
cosθ=√(p2−1)2(p2+1)2=p2−1p2+1
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