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In triangle PQR,if S is any …

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In triangle PQR,if S is any point on the side QR , show that PQ +QR + RP> 2PS.
  • 1 answers

Rahul Sharma 7 years, 10 months ago

In ΔPQS
Sum of any two sides is greater than the third side.
So, PQ + QS > PS ......(1)

In ΔPSR
Sum of any two sides is greater than the third side.
So, PR + SR > PS ...(2)

Adding equations (1) and (2)

PQ + PR + QS + SR > PS + PS

PQ + PR + QR > 2PS   [ QS + SR = QR]

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