3 (a-b)(b-c)(c-a) how to solve this?

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Rashmi Bajpayee 8 years, 7 months ago
Here a - b + b - c + c - a = 0,
therefore, its value is
{tex}{\left( {a - b} \right)^3} + {\left( {b - c} \right)^3} + {\left( {c - a} \right)^3}{/tex}
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