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In a parallelogram ABCD in which …

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In a parallelogram ABCD in which the bisector of angle A and angle B intersect at point P. Prove that angle APB =90

Posted by Sparsh Shrivastava 7 years, 11 months ago

CBSE > Class 09 > Mathematics

1 answers

Mahesh Kadian 7 years, 11 months ago

Given =ABCD is a parallelogram To prove= angle APB is equal to 90 Proof= angle A = 45 ( AP bisect angle A) = Angle B = 45 ( BP bisect angle B) In triangle abc( by angle sum property of triangle) Angle A + Angle B + Angle P = 180 45 + 45 + Angle P = 180 Angle P =180 -90 Angle P = 90 or angle APB = 90

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