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Cot theta+cosec theta-1/cot theta-cosec theta+1

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Cot theta+cosec theta-1/cot theta-cosec theta+1
  • 1 answers

Soumya Ghoshal 7 years, 10 months ago

(cotA+cosecA-1)/(cotA-cosecA+1)

=(cotA+cosecA-1)²/(cotA+cosecA-1)(cotA-cosecA+1)

=(Cot²A+cosec²A+1+2cotAcosecA-2cotA-2cosecA)/(cot²A-cosec²A-1+2cosecA)

={2cosec²A-2cosecA+2cotA(cosecA-1)}/(2cosecA-2)

={2cosecA(cosecA-1)+2cotA(cosecA-1)}/2(cosecA-1)

=2(cosecA-1)(cosecA+cotA)/2(cosecA-1)

=cosecA+cotA

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