{[80×20]+[62×1/6]}×[(4/7)12÷(4/7)10]
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Rashmi Bajpayee 6 years, 8 months ago
{tex}\left[ {\left\{ {{8^0} \times {2^0}} \right\} + \left\{ {{6^2} \times {1 \over 6}} \right\}} \right] \times \left[ {{{\left( {{4 \over 7}} \right)}^{12}} \div {{\left( {{4 \over 7}} \right)}^{10}}} \right]{/tex}
= {tex}\left[ {\left\{ {1 \times 1} \right\} + \left\{ {{6^{2 - 1}}} \right\}} \right] \times \left[ {{{\left( {{4 \over 7}} \right)}^{12 - 10}}} \right]{/tex}
= {tex}\left[ {1 + 6} \right] \times \left[ {{{\left( {{4 \over 7}} \right)}^2}} \right]{/tex}
= {tex}7 \times {4 \over 7} \times {4 \over 7}{/tex}
= {tex}{{16} \over 7}{/tex}
= {tex}2{2 \over 7}{/tex}
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