The sum of the squares of …
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Posted by Md Kaif 7 years, 11 months ago
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Rajeev Malhotra 7 years, 11 months ago
let the three numbers are x, x+1 and x+2.
so (x)2+(x+1)2+(x+2)2 = 77
x2+x2+2x+1+x2+4x+4= 77
3x2+6x+5 = 77
3x2+6x -72 =0
3x2+18x-12x-72 =0
3x(x+6)-12(x+6)=0
(3x-12)(x+6)=0
3x-12=0 or x+6 =0
3x=12 or x= -6
x=12/3=4 nor x=-6
x =4 , x=-6 is not possible because a natural number can not be negative.
so numbers are 4,5 and 6.
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