A tent in the form of …

Diameter of cyliner = 24m
{tex}\therefore{/tex} radius of cylinder = radius of cone = 12m
Height of cylinder = 11m
Total height of tent = 16m
{tex}\therefore{/tex} Height of cone = 16-11 = 5m
Now, l² = r² + h²
{tex}\Rightarrow{/tex} l² = 12² + 5²
{tex}\Rightarrow{/tex} l² = 144 + 25 = 169
{tex}\Rightarrow{/tex} l = {tex}\sqrt {169} {/tex} = 13m
{tex}\therefore{/tex} Canvas required for tent = curved surface area of cone + curved surface area of cylinder
= {tex}\pi{/tex}rl + 2{tex}\pi{/tex}rh
= {tex}\frac{22}{7}{/tex}{tex}\times{/tex}12{tex}\times{/tex}13+2{tex}\times{/tex}{tex}\frac{22}{7}{/tex}{tex}\times{/tex}12{tex}\times{/tex}11
= {tex}\frac{22}{7}{/tex}{tex}\times{/tex}12[13+2{tex}\times{/tex}11]
=​​​​​​​ {tex}\frac{22}{7}{/tex}{tex}\times{/tex}12{tex}\times{/tex}35
= 22{tex}\times{/tex}12{tex}\times{/tex}5=1320m²