From a solid cylinder whose height …
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Sia ? 6 years, 5 months ago
Diameter of the solid cylinder = 1.4 cm
{tex}\therefore{/tex} Radius of the solid cylinder = 0.7 cm
{tex}\therefore{/tex} Radius of the base of the conical cavity = 0.7 cm
Height of the solid cylinder = 2.4 cm
{tex}\therefore{/tex} Height of the conical cavity = 2.4 cm
{tex}\therefore{/tex} Slant height of the conical cavity = {tex}\sqrt{(0.7)^2\;+\;(2.4)^2\;}\;=\sqrt{0.49\;+5.76}=\;\sqrt{6.25}\;=\;2.5{/tex} cm
{tex}\therefore{/tex} TSA of remaining solid
= 2{tex}\pi{/tex}(0.7) (2.4) + {tex}\pi{/tex}(0.7)2 + {tex}\pi{/tex}(0.7) (2.5)
= 3.36{tex}\pi{/tex} + 0.49{tex}\pi{/tex} + 1.75{tex}\pi{/tex}
= 5.6{tex}\pi{/tex}
= 5.6 {tex}\times{/tex} {tex}\frac{22}7{/tex}
= 17.6 cm 2 = 18 cm 2 (to the nearest cm 2)
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