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Parallelogram on the same base and …

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Parallelogram on the same base and between the same parallel are equal in area prove it

    • Posted by Shashank Nautiyal 7 years, 11 months ago

    CBSE > Class 09 > Mathematics
    • 1 answers

    Khushi Singh 7 years, 11 months ago

    Let's take two parallelogram ABCD and EFCD on the same base DC and between same parallels AF and DC..........to prove=(ABCD=EFCD)...............in ∆ADE and ∆BCF,angleDAE=angleCBF(corresponding angles from AD //BCand transversa AF).................angleAED=angleBFC(corresponding angles from ED//DC and transversal AF).....therefore,angleADE=angleBCF(angle sum property of triangle)...also,AD=BC,hence∆ADEis congruent to∆BCF(ASA rule)....... therefore,ar(ADE)=at(BCF)....now,ar(ABCD)=at(ADE)+ar(EDCB)=ar(EFCD).........hence proved that ar(ABCD)=ar(EFCD)

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