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Two circles of radii 10 cm and 8 cm interest at two points and the length of the common chord is 12 cm . Find the distance between their centre

Posted by Rajeev Kumar 7 years, 11 months ago

CBSE > Class 09 > Mathematics

3 answers

Khushi Singh 7 years, 11 months ago

You now have four right triangles formed by the radii of each circle with the perpendicular drawn from each center point to the chord of intersection, we will use one triangle from each circle OB = 8, BI = 6, find OI by Pythagorean Theorem BI2 + OI2 = OB2 36 + OI2 = 64 OI2 = √ 28 OI = 5.292 -------------------------------------------------------------- BP = 10, BI = 6, find PI This is a 3 - 4- 5 right triangle: 6, PI = 8, 10 -------------------------------------------------------------- Therefor the distance between the centers: PO = OI + BI PO = 5.292 + 8 PO = 13.29

0Thank You

Anand Raj 7 years, 11 months ago

13.3

0Thank You

Khushi Singh 7 years, 11 months ago

12 cm

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CBSE > Class 09 > Mathematics