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Find the sum of all 3 digit no. Which leave a remainder 3 when divided by 5 .

Posted by Kanishk Goyal 8 years, 11 months ago

CBSE > Class 10 > Mathematics

1 answers

Naveen Sharma 8 years, 11 months ago

First 3 Digit Number that leaves remainder 3 when divided by 5 is 103.

and last will be 998

A.P. = 103, 108, 113, ..................., 998

first term a = 103

Common Difference d = 5

nth term = 998

n = ?

as we know

nth term = a + ( n-1)d

998 = 103 + ( n-1)5

895/ 5 = n -1

179 = n -1

n = 180

now find sum of 180 terms of AP

S_{180 =}180/ 2 ( 103 + 998 )

=> S_{180 =}90 * 1001

=> S_{180 =}900090

0Thank You

ANSWER

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