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Solve 4x²-2(a²+b²)x+a²b²=0 find the value of x

Posted by Kanishk Goyal 8 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Shweta Gulati 8 years, 5 months ago

a= 4

b= -2(a²+b²)

c= a²b²

Using Discriminant formula,

D= b²-4ac

[-2(a²+b²)]²-4 x4xa²b²

4(a⁴+b⁴+2a²b²)-16a²b²

(2a²-2b²)²

x= $(- b \pm \sqrt{D}) / 2 a$

x= [2(a²+b²)+2(a²-b²)]/8 = 4a²/8 = a²/2

x= [2(a²+b²)-2(a²-b²)]/8 = 4b²/8 = b²/2

6Thank You

ANSWER

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