Solve 4x2-2(a2+b2)x+a2b2=0 find the value of …
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Shweta Gulati 8 years, 4 months ago
a= 4
b= -2(a2+b2)
c= a2b2
Using Discriminant formula,
D= b2-4ac
[-2(a2+b2)]2-4 x4xa2b2
4(a4+b4+2a2b2)-16a2b2
(2a2-2b2)2
x=
x= [2(a2+b2)+2(a2-b2)]/8 = 4a2/8 = a2/2
x= [2(a2+b2)-2(a2-b2)]/8 = 4b2/8 = b2/2
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