A square of diagonal is Inscribed …

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Sia ? 6 years, 5 months ago
We know that diagonal of square of side a={tex}\sqrt 2\ a{/tex}
{tex}\Rightarrow{/tex} 8={tex}\sqrt 2\ a{/tex}
{tex}\Rightarrow\ a=4\sqrt 2{/tex}
Area of square={tex}(4\sqrt2)^2=32{/tex}
Diameter of a circle = Diagonal of a square = 8cm
{tex} \Rightarrow {/tex} Radius of a circle = 4cm
Area of required region
= Area of a circle - Area of a square
{tex} = \left[ {\pi {{(4)}^2} - 32} \right]c{m^2}{/tex}
{tex} = \left( {16\pi - 32} \right)c{m^2}{/tex}
0Thank You