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A compound forms hcp structure. What …

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A compound forms hcp structure. What is the total number of voids in 0.5 mol of it? How many of these are tetrahedron voids?

Posted by Tarak Singh 7 years, 11 months ago

CBSE > Class 12 > Chemistry

1 answers

Mansi Choudhary 7 years, 11 months ago

Number of atoms in close packaging = 0.5 mol 1 has 6.022 ×10 23 particles So that, Number of close−packed particles = 0.5 × 6.022 × 1023 = 3.011 × 1023 Number of tetrahedral voids = 2 × number of atoms in close packaging Plug the values we get, Number of tetrahedral voids = 2 × 3.011 × 1023 = 6.022 × 1023 Number of octahedral voids = number of atoms in close packaging So that, Number of octahedral voids = 3.011 × 1023 Total number of voids = Tetrahedral void + octahedral void = 6.022 × 1023 + 3.011 × 1023 = 9.03 × 1023

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