In how many ways the letters …
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Sahdev Sharma 8 years, 4 months ago
The letters have to be arranged in such a way that there are always 4 letters between P and S.
Therefore, in a way, the places of P and S are fixed. The remaining 10 letters in which there are 2 Ts can be arranged in {tex}10!\over 2 !{/tex} ways
Also, the letters P and S can be placed such that there are 4 letters between them in {tex} 2 \times 7 = 14{/tex} ways.
Therefore, by multiplication principle, required number of arrangements in this case = {tex}{10!\over 2!}\times 14 = {/tex}
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