A tent is shaped of a …

Height of the cylinder = 3 m.
Total height of the tent above the ground = 13.5 m
{tex}\therefore{/tex} height of the cone = (13.5 - 3)m = 10.5 m
Radius of the cylinder = radius of cone = 14 m
Curved surface area of the cylinder = {tex}2 \pi r h \mathrm { m } ^ { 2 } = \left( 2 \times \frac { 22 } { 7 } \times 14 \times 3 \right) \mathrm { m } ^ { 2 } = 264 \mathrm { m } ^ { 2 }{/tex}
{tex}\therefore \quad l = \sqrt { r ^ { 2 } + h ^ { 2 } } = \sqrt { 14 ^ { 2 } + ( 10.5 ) ^ { 2 } } = \sqrt { 196 + 110.25 } = \sqrt { 306.25 } = 17.5{/tex}
{tex}\therefore{/tex} Cured surface area of the cone = {tex}\pi r l = \left( \frac { 22 } { 7 } \times 14 \times 17.5 \right) \mathrm { m } ^ { 2 } = 770 \mathrm { m } ^ { 2 }{/tex}
Let S be the total area which is to be painted.Then,
S = Curved surface area of the cylinder + Curved surface area of the cone
{tex}\Rightarrow{/tex} S = (264 + 770) m² = 1034 m²
Hence, Cost of painting = S {tex}\times{/tex} Rate = Rs{tex}( 1034 \times 2 ){/tex}= Rs2068