A piece of wire having resistance …
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Posted by Swapnil Kanwar 8 years ago
- 3 answers
Naveen Sharma 8 years ago
Let Original Resistance is R.
We know that {tex}R \propto l{/tex}
So, when the wire is cut into four equal parts, the resistance of each part is {tex}{1\over 4}{th }{/tex} of the original substance.
Hence, R1 = R2 = R3 = R4 = {tex}{R\over 4}{/tex}
Also Let new resistance is R'.
When these 4 parts are joined in parallel,
Then {tex}{1\over R'}= {4\over R} + {4\over R} + {4\over R} + {4\over R}{/tex}
{tex}=> {1\over R'} = {16\over R}\\ => R' = {R\over 16}{/tex}
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Swapnil Kanwar 7 years, 11 months ago
0Thank You