Prove that sum of Opposite angles …

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Posted by Shivani Gusain 8 years, 3 months ago
- 2 answers
Varun Banda 8 years, 3 months ago
Given : Let ABCD is cyclic quadrilateral.
To prove : ∠A + ∠C = 180° and ∠B + ∠D = 180°.
Construction: join OB and OD.
Proof :
∠BOD = 2 ∠BAD ∠BAD = 1/2∠ BOD
Similarly∠BCD = 1/2 ∠DOB ∠BAD + ∠BCD
= 1/2∠BOD + 1/2 ∠DOB
=1/2(∠ BOD + ∠DOB)
= (1/2)X360° = 180°
Similarly ∠B + ∠D = 180°
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Golua Singham 8 years, 3 months ago
1Thank You