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Find the natural number from 101to …

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Find the natural number from 101to 999 which are divisible by 2 and 5
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Sia ? 6 years, 5 months ago

Natural numbers between 101 and 999 divisible by both 2 and 5, i.e., divisible by L.C.M of 2 and 5 i.e., 10, are 110, 120, 130 ,...., 990.

so, this forms an AP 110,120....,990., where first term({tex}a{/tex})=110 and common difference({tex}d{/tex})=120-110=10, and last term({tex}l{/tex})=990

Let  {tex}l = {a_n} = a + (n - 1)d{/tex}

Then, {tex}990 = 110 + (n - 1) \times 10{/tex}

{tex} \Rightarrow n = 89{/tex}

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