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x+y+z=0show that x³+y³+z³=3xyz any other method …

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x+y+z=0show that x³+y³+z³=3xyz any other method to solve it
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बेबि बीच 8 years, 3 months ago

x+y+z =0 x + y = -z ------(i) Cube both the sides, (x+y)^3 = -z ^3 x^3 + y^3 +3xy (x+y) =-z^3 Substitute for x+ y as -z from eq. (i) Therefore, x^3 + y^3 + 3xy(-z) = -z^3 x^3 + y^3 -3xyz = -z^3 x^3 + y^3 + z^3 = 3xyz.
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