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sum of first 14 term of an ap is 1505 and its first term is 10 find its 25 term

Posted by Kapil Verma 8 years, 4 months ago

CBSE > Class 10 > Mathematics

4 answers

Danush Adithyaa 8 years, 4 months ago

Ans is 135

0Thank You

Sai Deep 8 years, 4 months ago

S14=1505 &A=10 we know that Sn=n/2[2a+(n-1)d ] here S14=14/2[2×10 +1(14-1)d ] 1505 = 7(20+13d) 1505/7=20+13d 215=20+13d 215-20=13d 195=13d d=195/13 d=15 Now A25=a+24d = 10+24×15 = 10+360 A25=370 is the answer

0Thank You

Anandjot Dhaliwal 8 years, 4 months ago

S14=1505 1505=n/2 (2a+(n-1)d 1505=14/2 (2 (10)+(14-1)d 1505=7 (20+13)d 1505=7 (43)d 1505=301 (d) 5=do A25=a+24d 10+24×5 10+120 130

1Thank You

Anandjot Dhaliwal 8 years, 4 months ago

Answer is 120

2Thank You

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