Factorise 8a3-b3-12a2b+6ab2
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Posted by Tushar Varshney 7 years, 10 months ago
- 1 answers
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Soumya Ghoshal 7 years, 10 months ago
8a³-b³-12a²b+6ab²
=(2a-b)(4a²+2ab+b²)-6ab(2a-b)
=(2a-b)(4a²+2ab+b²-6ab)
=(2a-b)(4a²-4ab+b²)
=(2a-b){(2a)²-2×2a×b+(b)²}
=(2a-b)(2a-b)²
=(2a-b)(2a-b)(2a-b)
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