Three photo diodes D1,D2 ,D3 are …
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Varun Banda 8 years ago
λmax1=hcE=6.6×10−34×3×1082×1.6×10−19=6.18×10−7 mλmax2=hcE=6.6×10−34×3×1082.5×1.6×10−19=3.96×10−7 mλmax3=hcE=6.6×10−34×3×1083×1.6×10−19=4.125×10−7 m Given λ=6000A=6×10−7 m
For detection of optical signal the wavelength of incident energy radiation must be greater. It is true only for D2 .Only D2 can detect the radiation
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