Find the value of tan1°tan2°tan3........tan89°.
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Posted by Dhruvrajsinh Jadeja 8 years, 4 months ago
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Dharmendra Kumar 8 years, 4 months ago
tan1°tan2°tan3°.........tan89°=tan(90°-89°)tan(90°-88°)tan(90°-87°)...............tan(90°-46°)tan45°tan46°.....tan89°
= cot89°cot88°cot87°..........cot46°tan45°tan46°......tan89° [by using identity tan(90°-A)= cotA]
={tex}1\over tan89°{/tex}×{tex}1\over tan88°{/tex}×.........{tex}1\over tan46°{/tex}×tan45°×tan46°×......tan88°×tan89°
= tan45° =1
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