Find √i+√-i
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Rishu Mathematician 8 years, 4 months ago
Solve:
{tex} √i+√(-i){/tex}
{tex}=√(e^(i π/2) )+√(〖-e〗^(i π/2) ){/tex}
{tex}=〖e〗^(i π/4)+ie^(i π/4){/tex}
{tex}=〖e〗^(i π/4) (1+i){/tex}
{tex}=〖e〗^(i π/4) (√2 e^(i π/4)){/tex}
{tex}=√2 e^(i π/2){/tex}
{tex}=i√2{/tex}
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