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If P(2,4) is equidistant from Q(7,0) …

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If P(2,4) is equidistant from Q(7,0) and R (X,9), find the value of X. Also find the distance PQ.

    • Posted by Himesh Kaushik 8 years, 11 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Naveen Sharma 8 years, 11 months ago

    Given: P(2,4) is equidistnat from Q(7,0) and R(X,9).

    then PQ = PR

    Using Distance Formula : = (x2-x1)2 + (y2- y1)2

    PQ = 25 + 16  = 41

    PR = (x-2)2 + (5)2

    PQ = PR 

    Sqauring Both Side, We get 

    x2 + 4 -4x + 25 = 41

    => x2 - 4x -12 = 0

    => x2 - 6x +2x -12 = 0

    => x(x-6) +2(x-6) = 0

    => (x-6) (x+2) = 0

    => x = -2 , 6 

    0Thank You

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