A path of 4m width run …
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Sia ? 6 years, 1 month ago
Let x be the radius of the semi-circular grassy plot.
Given,
Circumference of grassy plot = 16337m
⇒2r+πr=16337m=11447m
⇒(2+π)r=11447m
⇒367r=11447m
⇒r=114436=2869m
∴ Radius of semi-circular grassy plot =2869m
Then, radius of outer semi-circle =2869m+4m=3229m
Area of path = Area of outer semi-circle - Area of inner semi-circle
=12π(3229)2−12π(2866)2
=12π(3229+2869)(3229−2869)
=12×227×6089×369
= 424.63m2
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