2 sin 68/cos 22 -2 cot …

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Sia ? 6 years, 5 months ago
{tex}\frac{{2\sin 68^\circ }}{{\cos 22^\circ }} - \frac{{2\cot 15^\circ }}{{5\tan 75^\circ }} - \frac{{3\tan 45^\circ \tan 20^\circ \tan 40^\circ \tan 50^\circ \tan 70^\circ }}{5}{/tex}
{tex} = \frac{{2\sin \left( {90^\circ - 22^\circ } \right)}}{{\cos 22^\circ }} - \frac{{2\cot \left( {90^\circ - 75^\circ } \right)}}{{5\tan 75^\circ }}{/tex} {tex} - \frac{{3\tan 45^\circ \tan \left( {90^\circ - 70^\circ } \right)\tan \left( {90^\circ - 50^\circ } \right)\tan 50^\circ \tan 70^\circ }}{5}{/tex}
{tex} = \frac{{2\cos 22^\circ }}{{\cos 22^\circ }} - \frac{{2\tan 75^\circ }}{{5\tan 75^\circ }} - \frac{{3 \times 1 \times \cot 70^\circ \times \tan 50^\circ \times \frac{1}{{\cot 50^\circ }} \times \frac{1}{{\cot 70^\circ }}}}{5}{/tex}
{tex} = 2 - \frac{2}{5} - \frac{3}{5}{/tex}
{tex} = \frac{{10 - 2 - 3}}{5} = \frac{5}{5} = 1{/tex}
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