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Construct a ∆ABC in which AB=6.5cm …

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Construct a ∆ABC in which AB=6.5cm , B=60° and BC=5.5cm. Also construct a triangle ABC similar to ∆ABC whose each side is 3/2 times the corresponding side of the ∆ABC
  • 2 answers

Sia ? 6 years, 5 months ago

 
Steps of construction:

  1. Draw a line segment AB = 6.5cm.
  2.  At B construct {tex}\angle ABX = 60^\circ {/tex}.
  3. With B as centre and radius BC = 5.5cm draw an arc intersecting BX at C.
  4. Join AC. Triangle so obtained is the required triangle.
  5. Construct an acute angle ∠BAY at A on opposite side of vertex C of {tex}\Delta ABC{/tex}
  6. Locate 3 points A1, A2, A3 on AY such that AA1 = A1A2 = A2A3
  7. Join Ato B and draw the line through Aparallel to A2B intersecting the extended line segment AB at B'.
  8. Draw a line through B' parallel to BC intersecting the extended line segment AC at C'.
  9. {tex}\triangle{/tex}AB'C' so obtained is the required triangle

Gautam Tanwar 4 years, 11 months ago

Construct triangle ABC in which AB=6.5 cm, B=600 and BC=5.5 cm. Then construct another triangle (with construction steps) whose sides are of the corresponding sides of the ΔABC.
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