No products in the cart.

13.8 exercise question number 7 and …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

13.8 exercise question number 7 and 9 explain everything critically
  • 1 answers

Kanha Vashu Rai 8 years, 2 months ago

Let r be the radius of the sphere. Given : surface area of a sphere= 154cm^2 Since 4pier^2= 154 =r^2 =154×7/22×4 r= 7/2cm Hence , volume of a sphere= 4/3pie (7/2)^2 "4/3pier^2" = 4/3×22/7×7/2×7/2×7/2 = 11×7×7/3 = 179.667= 179.67cm^3
https://examin8.com Test

Related Questions

2x²+[1×(8x²)^-1]+1
  • 0 answers
What is 38747484±393884747
  • 0 answers
3√2×4√2×12√32
  • 0 answers
X³-12x²+39x-28
  • 0 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App