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-3√2/√6+√3 + 4√3/√6+√2

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-3√2/√6+√3 + 4√3/√6+√2

Posted by Rupy Pandher Rupy 4 months, 2 weeks ago

CBSE > Class 09 > Mathematics

1 answers

Shiwam Barnwal 4 months, 2 weeks ago

-3√2/√6+√3+4√3/√6+√2 =-3√2/√3*√2+√3+4√3/√3*√2+√2 =-3/√3+√3+4/√2+√2 =(-3√2+3√2+4√3+2√3) /√6 =6√3/√6 =6/√2 =3√2

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