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Manjeetkumar14 Manjeetkumar14 1 year, 4 months ago

Hi

Karthik Das 2 years, 2 months ago

If <BAD = 108°. Find: (1) BOC (ii)<DCF (iii) DBO

Karthik Das 2 years, 2 months ago

In the given figure, ABCD is a cyclic quadrilateral, where DB = DC CF is a tangent to the circle at C. If <BAD = 108°. Find: (1) BOC (ii)<DCF (iii) DBO
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Vanshika Sarraf 2 years, 3 months ago

8+x
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Mathematics Math 2 years, 5 months ago

9X90
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Fuzz Rudraksh 2 years, 6 months ago

Vip

Harjit Singh 2 years, 11 months ago

Excercise solution
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Arpit Airen 3 years, 7 months ago

Here you have to matrix addition mean you have to simple add corresponding elements of the matrices.

For eg.

[ a b] + [c d] = [a+c b+d]

Similarly, you can add corresponding elements for any order.

Just make sure to add a11 with b11

a12 with b12

a21 with b21

a22 with b22 and soon.

8+7
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Sia ? 3 years, 7 months ago

15

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Sia ? 3 years, 8 months ago

Please ask question with complete information.

Dvh
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Pramesh Kadraka 2 years, 9 months ago

A nswar the following questions each in about 50 word

Gauri Patel 3 years, 8 months ago

19.8 cm
1.6
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Suhani . V 3 years, 10 months ago

Let cost of apples be rs x Let cost of grapes be Rs y A. T. Q 2x+1y=160 ---------- 1 4x+2y=300 ---------- 2

Archana Bhandari 3 years, 11 months ago

Let cost each kg of apples = Rs x Cost of each kg of grapes = Rs y Given that the cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs 160 So that 2 x + y = 160 … (i) 2x = 160 - y x = (160 – y)/2 Let y = 0 , 80 and 160, we get x = (160 – ( 0 )/2 = 80 x = (160- 80 )/2 = 40 x = (160 – 2 × 80)/2 = 0 x 80 40 0 y 0 80 160 Given that the cost of 4 kg of apples and 2 kg of grapes is Rs 300 So we get 4x + 2y = 300 … (ii) Dividing by 2 we get 2x + y = 150 Subtracting 2x both side, we get y = 150 – 2x Putting x = 0 , 50 , 100 we get y = 150 – 2 × 0 = 150 y = 150 – 2 × 50 = 50 y = 150 – 2 × (100) = -50 x 0 50 100 y 150 50 -50 Algebraic representation, 2x + y = 160 … (i) 4x + 2y = 300 … (ii) Graphical representation, Graph 3

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