The cost of 2 kg of …

Let cost of apples be rs x Let cost of grapes be Rs y A. T. Q 2x+1y=160 ---------- 1 4x+2y=300 ---------- 2

Let cost each kg of apples = Rs x Cost of each kg of grapes = Rs y Given that the cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs 160 So that 2 x + y = 160 … (i) 2x = 160 - y x = (160 – y)/2 Let y = 0 , 80 and 160, we get x = (160 – ( 0 )/2 = 80 x = (160- 80 )/2 = 40 x = (160 – 2 × 80)/2 = 0 x 80 40 0 y 0 80 160 Given that the cost of 4 kg of apples and 2 kg of grapes is Rs 300 So we get 4x + 2y = 300 … (ii) Dividing by 2 we get 2x + y = 150 Subtracting 2x both side, we get y = 150 – 2x Putting x = 0 , 50 , 100 we get y = 150 – 2 × 0 = 150 y = 150 – 2 × 50 = 50 y = 150 – 2 × (100) = -50 x 0 50 100 y 150 50 -50 Algebraic representation, 2x + y = 160 … (i) 4x + 2y = 300 … (ii) Graphical representation, Graph 3