Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Arobindo Borah 3 years, 10 months ago
- 1 answers
Posted by Gurbaksh Kular 3 years, 11 months ago
- 1 answers
Rajan Kumar Pasi 3 years, 11 months ago
Sol = Let the unknown number be, x
Thus according to the question, {tex}\huge
{
x+\frac{15}{32} = -\frac{7}{11}
}{/tex}
So, {tex}\huge
{
x=-\frac{15}{32} -\frac{7}{11}
}{/tex}
=> {tex}\huge
{
x=\frac{(-15\times 11)-(7\times32)}{32\times 11}
}{/tex}
=> {tex}\huge
{
x=\frac{(-165)-(224)}{352}
}{/tex}
=> {tex}\huge
{
x=\frac{-389}{352}
}{/tex}
Please write the grammar of the question properly.
It should be like this:
What number should be added to 15 upon 32 to get minus 7 upon 11 ?
Posted by Anjali Panjiyar 3 years, 11 months ago
- 1 answers
Yogita Ingle 3 years, 11 months ago
2x-y=9........ (i)
3x+y=0 ........ (ii)
add (i) and (ii), we get
5x = 9
x = 9/5
Put x = 9/5 in (ii) , we get
3(9/5) + y = 0
27/5 + y = 0
y = -27/5
Posted by Harsh Tripathi 3 years, 11 months ago
- 2 answers
Shubham Mishra 3 years, 9 months ago
Posted by Harsh Tripathi 3 years, 11 months ago
- 0 answers
Posted by Riya Rani 3 years, 11 months ago
- 0 answers
Posted by Deepak Bagga 3 years, 11 months ago
- 1 answers
Posted by Vinod Kumar 4 years ago
- 0 answers
Posted by Vineet Raj 4 years ago
- 2 answers
Shubham Mishra 3 years, 9 months ago
Posted by Ekamdeep Singh 4 years ago
- 1 answers
Yogita Ingle 4 years ago
(4a+3b)2 - (4a-3b)2 + 48ab
= (4a)2 + (3b)2 + 2(4a)(3b) + (4a)2 + (3b)2 - 2(4a)(3b)+ 48ab
= 16a2 + 9b2 + 24ab + 16a2 + 9b2 - 24ab + 48ab
= 16a2 + 16a2 + 9b2 + 9b2 + 48ab
= 32a2 + 18b2 + 48 ab
Posted by Karan Rawat 4 years ago
- 2 answers
Parth Rungta 4 years ago
Posted by Nesheema Banu 4 years, 1 month ago
- 1 answers
Posted by Nava Mani 4 years, 1 month ago
- 1 answers
Rajan Kumar Pasi 3 years, 11 months ago
Q. {tex}\LARGE { \frac{5}{4}}{/tex} times a number is 10 more than the number. Find the number?
Sol. =
Covert the statement step by step into a mathematical expression.
=> Let the unknown number be, x
=> {tex}\LARGE { \frac{5}{4}}{/tex} times a number = {tex}\LARGE { \frac{5}{4}\times x}{/tex}
=> 10 more than the number = {tex}\LARGE {10 + x}{/tex}
=> Therefore, {tex}\LARGE { \frac{5}{4}\times x}{/tex}{tex}\LARGE { = 10 + x}{/tex}
{tex}\huge {=> 5\times x = 4\times (10+x)}\\
\huge{=> 5 x= 40+4x }\\
\huge{=> 5 x-4x= 40 }\\
\huge{=> x= 40 }\\{/tex}
Final answer, x = 40.
Posted by Geesha Raj 4 years, 1 month ago
- 0 answers
Posted by Fenil Rana 4 years, 1 month ago
- 0 answers
Posted by Pardeep Kumar 4 years, 1 month ago
- 1 answers
Rajan Kumar Pasi 3 years, 11 months ago
The very easy question looks like of class 6.
{tex}\huge{=> \frac{2.7}{100}}\\
\huge{=> \frac{27}{10\times 100} }\\
\huge{=> \frac{27}{1000}}\\
\huge{=>0.027}\\ Final \ answer.{/tex}
Posted by Palak Raj 4 years, 2 months ago
- 1 answers
Rajan Kumar Pasi 3 years, 11 months ago
The greatest 5-digit number is 99999 and
The smallest 5-digit number is 10000.
But by using different digits,
The greatest 5-digit number is 98765 and using 4 at the tenth place we will get
=> 98746
Similarly, The smallest 5-digit number is 10234 and using 4 at the tenth place we will get
=> 10243
So, according to the conditions given in the question:
The greatest 5-digit number is 98746 and
The smallest 5-digit number is 10243, having 4 at the tenth place and with different digits.
Posted by Ajay Kumar 4 years, 2 months ago
- 0 answers
Posted by Faiz Ahmad 4 years, 2 months ago
- 1 answers
Rajan Kumar Pasi 3 years, 11 months ago
It is a question of construction.
You should use scale, rounder (compass)and pencil to construct it.
Sol: First write all the sides or angles given (if any)
Name of quadrilateral = ABCD
Sides: AB=4cm
AC=6cm
CD=5.4cm
DA=5.4cm
First make a rough sketch to have an idea of the required sketch.
Posted by Dhatla Komalatha Komalatha 4 years, 2 months ago
- 1 answers
Rajan Kumar Pasi 3 years, 11 months ago
Using construction steps of 45degree you an make it.
and if you are allowed to use the protractor then only you can make 40 degree with it.
Posted by Pradyumna Singh Shahi 4 years, 2 months ago
- 1 answers
Rajan Kumar Pasi 3 years, 11 months ago
A mistake in the question, "class assado" = cast's a shadow.
Sol:
From eq. 1 and eq. 2 we will get:
{tex}\huge {=>\ \frac{6}{y+3} = \frac{1.5}{3} }\\ \huge {=>\ 6\times3 = 1.5\times(y+3) }\\ \huge {=>\ \frac{18}{1.5} = y+3}\\ \huge {=>\ 12 = \frac{y}{3} }\\ \huge {=>\ 12-3 = y }\\ \huge {=>\ y=9 }\\{/tex}
Thus, the lady is 9 meters away from the lamp post.
All the best :-)...
Posted by Siddharth711 Gamer 4 years, 2 months ago
- 0 answers
Posted by Vaishnavi Devi 4 years, 2 months ago
- 1 answers
Posted by Anand Soni 4 years, 2 months ago
- 0 answers
Posted by Manoj Kumar 4 years, 3 months ago
- 0 answers
Posted by Aryan Raj 4 years, 3 months ago
- 3 answers
Posted by Mohammed Sami 4 years, 3 months ago
- 2 answers
Rajan Kumar Pasi 3 years, 11 months ago
{tex}\huge{=>\ 3.14\times \frac{10.5}{2}\times 10}\\ \huge{=>\ \frac{314}{100}\times \frac{105}{200}\times 10}\\ \huge{=>\ 164.85\ \text{cm}^2}\\{/tex}
Posted by Mohammed Sami 4 years, 3 months ago
- 1 answers
Posted by Mohinder Kaur 4 years, 3 months ago
- 0 answers
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Shubham Mishra 3 years, 9 months ago
0Thank You