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Ask QuestionPosted by Sumit Sharma 8 years, 2 months ago
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Posted by Simranjit Kaur Mehra 8 years, 2 months ago
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Amar Kumar 8 years, 2 months ago
Work is the energy required to move an object against a force. Work is equal to the force times the distance the object moves.
W = F * s where W is work, F is force, and s is the displacement.
The SI unit for work is the joule.The SI units for work are the joule (J) or newton-meter (N * m) .
Posted by Alka Khan Khan 8 years, 2 months ago
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Naveen Sharma 8 years, 2 months ago
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Transpiration |
Guttation |
| 1. | In transpiration, water is lost in the form of water vapour. | In guttation, water is lost in the form of liquid droplets. |
| 2. | Water lost is pure water. | Water lost contains salts, sugars and amino acids. |
| 3. | Water is transpired through stomata, cuticle and lenticels. | Water is lost through hydathodes (chalk glands.) |
| 4. | It takes place in present of light when the temperature is higher. | It occurs during the cold hours of early morning and night. |
| 5. | It takes place in dry conditions which favour loss of water through diffusion. | It takes place in humid conditions which do not favour loss of water through diffusion. |
| 6. | It is controlled by a number of factors, the opening and closing of stomata being the main one. | It continues as long as adequate water supply in maintained and the conditions are cold and humid. |
| 7. | Excessive transportation under deficit water supply leads to wilting. | It never results in wilting as it does not take place under deficit water supply. |
Posted by Raushan Kumar 8 years, 2 months ago
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Posted by Rakhi Singh Tomar 8 years, 3 months ago
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Posted by Adari Srinivasarao 8 years, 3 months ago
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Posted by Hemant Singh 8 years, 3 months ago
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Naveen Sharma 8 years, 3 months ago
Given {tex}T = k p^a d^b E^c{/tex}
where k is a proportionally constant.
Substituting the dimensions of T, p, d and E,
we have
{tex} [T] = [[ML^{-1}T^{-2}]^ a [ML^{-3}]^ b [ML^2T^{ -2}]^ c {/tex}
Equating power of M, L, and T on both sides, we have
a + b + c = 0
–a –3b + 2c = 0
–2a – 2c = 1
Solving these equations, we get {tex}a = {-5\over 6}, \ b = {1\over 2} \ and \ c ={ 1\over 3}{/tex}
Posted by Monu Yadav 8 years, 3 months ago
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Himanshu Singhal 8 years, 3 months ago
the nucleus formed by the fusion of two polar nuclei in the embryo sac of a seed plant prior to fertilization —called also secondary nucleus
Posted by Santhosh Santhosh 8 years, 3 months ago
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Posted by Xavier Pradhan 8 years, 3 months ago
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Posted by Rishabh Raj 8 years, 3 months ago
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Posted by Saimi Rathore 8 years, 3 months ago
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Viplov Nirala 8 years, 3 months ago
Bronchial here refers to relation with bronchi or bronchioles.
Individuals suffer rom various bronchial diseases such as Bronchitis, Bronchiolitis etc.
Posted by Muhd Umar Ansari 8 years, 3 months ago
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