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    • Posted by Gokul Prasanth G 5 years, 4 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Harshit Agarwal 5 years, 4 months ago

    a system containing two equal and opposite charges separated by a finite distance is called electric dipole dipole dipole moment of electric dipole having charges q + and queue negative at a separation of two well that is a vector is equal to q 2L vector

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    • Posted by Gokul Prasanth G 5 years, 4 months ago

    CBSE > Class 12 > Physics
    • 2 answers

    Rahul Mehra 5 years, 4 months ago

    Electic field is defined as the space around the charged in which the force of attraction and repulsion can be experienced by other other charge kept at that point. Electric field lines is defined as the curves in which tangent to any point on field lines gives the direction of electric field

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    Alen Saklani 5 years, 4 months ago

    Electric field: The region surrounding a charge in which its electrical effects are perceptible (or can be seen) is called the electric field of the given charge. Electric field lines: Electric field lines are the ''imaginary'' lines drawn in a region of space time along which a free positive charge would move or allowed to do so. These lines originate at positive charge and terminate at negative charge.

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    • Posted by Nitesh Upadhyay 5 years, 4 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Yogita Ingle 5 years, 4 months ago

    Sunglasses do not have any power because both the surfaces of the glasses are equally curved.

    2Thank You

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    • Posted by Nitesh Upadhyay 5 years, 4 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    ? ? 5 years, 4 months ago

    In our eye real image is formed on retina......it means that the virtual image acts as object for eye lens whose real image is formed on retina ....the signals reach brain and it inverts the image so that it appears upright

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    • Posted by Mani Manisha 5 years, 4 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Nihira Nihira 5 years, 4 months ago

    Charges are quantised because no. of electrons cannot be transferred in fraction(e.g., 3.5,8.6 etc...). Charge transfer takes place through transfer of electrons.

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    • Posted by Nitesh Upadhyay 5 years, 4 months ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Sandeepani Satpathy 5 years, 4 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Gaurav Seth 5 years, 4 months ago

    The total number of electrons in an atom of Cu is 29 
    Given,
    mass=10g

    Molar mass= 63.5 
    Therefore,
    no. of moles of Cu = 10/63.5 = 0.157
    So,
    total numbers of electron =0.157*6.023*1023*29 =N(let).
    So,

    the toal charge due to N electrons is 
    Qe = N*e { e is the fundamental charge =1.6*10-19} 
         = 0.157*6.023*1023*29*1.6*10-19 
         = 4.387*105 C

    0Thank You

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    • Posted by Sandeepani Satpathy 5 years, 4 months ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Rudransh Bisht 5 years, 4 months ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Subodh Singh 5 years, 4 months ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Rinku Sheoran 5 years, 4 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    ? ? 5 years, 4 months ago

    Thats not true....it depends on if you are charging or discharging your cell...while discharging ...V=E-IR ....where v is terminal voltage , E is emf and I is current and R is resistance .....however during charging of cell its is V=E+IR.....

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    • Posted by Satvik Arya 5 years, 4 months ago

    CBSE > Class 12 > Physics
    • 2 answers

    Rohit Krishna 5 years, 4 months ago

    Please note that it is optical centre and not pole for a lens.

    0Thank You

    Rohit Krishna 5 years, 4 months ago

    There is no such case according to my knowledge.A ray of light parallel to principal axis is the one coming from infinity and hence after "refraction" it will definitely pass through the focus of the lens forming a real image.If in case the parallel ray has to pass through the optical centre(there is no refraction or deviation while passing through pole),it has to suffer other refractions and then pass finally through the pole rather than coming directly. •Or you can think logically.A ray parallel to principal axis,if passes through the optical centre never becomes parallel to principal axis as the optical centre itself is the centre of lens which also lies on principal axis and parallel rays never meet(here,ray of light and principal acis are parallel and hence they never neet).Therefore no such case is possible.

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    • Posted by Rohit Krishna 5 years, 4 months ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Abhinav Singh 5 years, 4 months ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Arpit Singh 5 years, 4 months ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Khushbu Thakur 5 years, 4 months ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Anil Kumar 5 years, 4 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Gaurav Seth 5 years, 4 months ago

    Gauss’s Law

    According to Gauss’s law, the total of the electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The total electric flux through a closed surface is zero if no charge is enclosed by the surface.

    • Gauss’s law is true for any closed surface, no matter what its shape or size.
    • The term q on the right side of Gauss’s lawincludes the sum of all charges enclosed by the surface. The charges may be located anywhere inside the surface.
    • In the situation when the surface is so chosen that there are some charges inside and some outside, the electric field [whose flux appears on the left side of Eq. (1.31)] is due to all the charges, both inside and outside S. The term q on the right side of Gauss’s law, however, represents only the total charge inside S.
    • The surface that we choose for the application of Gauss’s law is called the Gaussian surface. The Gaussian surface can pass through a continuous charge distribution.
    • Gauss’s law is useful for the calculation of the electrostatic field for a symmetric system.
    • Gauss’s law is based on the inverse square dependence on distance contained in the Coulomb’s law. Any violation of Gauss’s law will indicate departure from the inverse square law.

    •  

    4Thank You

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    • Posted by Anuj Singh 5 years, 5 months ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Sejal Korgaonkar 5 years, 5 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Ayush Vishwakarma?? 5 years, 4 months ago

    That is epsilon not. it's value is 8.85×10^-12F

    1Thank You

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    • Posted by Alen Saklani 5 years, 5 months ago

    CBSE > Class 12 > Physics
    • 3 answers

    Alen Saklani 5 years, 4 months ago

    Thnks both of u?

    2Thank You

    Ayush Vishwakarma?? 5 years, 4 months ago

    1/10N

    3Thank You

    Account Deleted 5 years, 4 months ago

    Divide the force experienced in vaccum by k ..i.e 80 {Fm =Fvac/k}

    2Thank You

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    • Posted by Mohit Kumar 5 years, 5 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Alen Saklani 5 years, 5 months ago

    Bro ,it is totally on you if you know that you are capable enough to cover the syllabus of class 12 then you can continue with class12 if not you should repeat class 11 because you should know basics for continuing in class 12?. I don't want to demotivate you but this is my opinion.

    6Thank You

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    • Posted by Satendra Kumar 5 years, 5 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Shoaib Khan 5 years, 5 months ago

    (A)To get maximum resistance ,combine all resistance in series (B) to get minimum resistance ..combine all resistance in parallel combination n resistance in series= R+R+R........+upto n = nR And n resistance in parallel = 1/R+1/R+1/R+........upto n = n/R So ..ratio = nR÷n/R= R^2

    1Thank You

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    • Posted by Jass . 5 years, 5 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Yogita Ingle 5 years, 5 months ago

    When a charged object is brought closer to another object (not touched), the original object doesn’t lose any charge and the other object gets charged as well with opposite polarity. The other extreme end of the newly charged object develops polarity same as that of the charged object. This type of charging is called charge by induction.

    1Thank You

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    • Posted by Jass . 5 years, 5 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Yogita Ingle 5 years, 5 months ago

    The Gaussian surface is known as a closed surface in three-dimensional space such that the flux of a vector field is calculated. These vector fields can either be the gravitational field or the electric field or the magnetic field.

    1Thank You

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    • Posted by Rohit Krishna 5 years, 5 months ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Akash Singh 5 years, 5 months ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Vidya Dwivedi 5 years, 5 months ago

    CBSE > Class 12 > Physics
    • 2 answers

    Jitesh Rana 5 years, 5 months ago

    No 9.1×0.00000000000000000000000000000000000000000000000000010

    1Thank You

    Nirmal Sharma 5 years, 5 months ago

    9.1×10power -31........?

    0Thank You

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    • Posted by Anna Varghese 5 years, 5 months ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Ajeet Sahu 5 years, 5 months ago

    CBSE > Class 12 > Physics
    • 4 answers

    Aditya Raj Lodhi 5 years, 5 months ago

    No

    0Thank You

    Siddhesh Raut 5 years, 5 months ago

    No, its not

    0Thank You

    Robinpreet Kaur 5 years, 5 months ago

    Noo

    0Thank You

    Sibte Hasan 5 years, 5 months ago

    No

    0Thank You

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    • Posted by Aditya Prajapati 5 years, 5 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Ayush Vishwakarma?? 5 years, 4 months ago

    At the centre if both are positive and same magnitude and distance r/2. And in the other case if they are negative then the netural point is similar to 1 which is above..........and if one is positive and one is negative then its netural point is away from distance r..like -r/2.

    1Thank You

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