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    • Posted by Khushi Ekka 11 months, 3 weeks ago

    CBSE > Class 12 > Physics
    • 2 answers

    Ayansh Pandey 11 months, 2 weeks ago

    To estimate the charge induced on each of the identical Styrofoam (or pith) balls suspended in a vertical plane, you can use Coulomb's Law, which states that the electrostatic force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between their centers. The formula for Coulomb's Law is \( F = \frac{{k \cdot q_1 \cdot q_2}}{{r^2}} \), where: - \( F \) is the electrostatic force, - \( k \) is Coulomb's constant (\(8.99 \times 10^9 \ \text{N m}^2/\text{C}^2\)), - \( q_1 \) and \( q_2 \) are the charges on the two objects, and - \( r \) is the separation between their centers. To estimate the charge, you would rearrange the formula as \( q = \sqrt{\frac{{F \cdot r^2}}{{k}}} \). Measure the force between the balls, the separation distance, and then use these values in the formula to estimate the charge on each ball. Keep in mind that this is an estimation and real-world factors such as air resistance may affect the accuracy of the results.

    0Thank You

    Shivam Singh 11 months, 2 weeks ago

    On the face of it MCQs

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    ANSWER

    • Posted by Ghahsjshdhdjdkgx Sbkyotsu8E 11 months, 3 weeks ago

    CBSE > Class 12 > Physics
    • 3 answers

    D Chahal 11 months ago

    Convex mirror

    0Thank You

    Kamal Kanwasi 11 months, 3 weeks ago

    convex bro

    0Thank You

    Lahar . 11 months, 3 weeks ago

    Since the image is diminished convex mirror has wider field of view .

    0Thank You

    ANSWER

    • Posted by Sakshi Singh 11 months, 3 weeks ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Ajeet Chauhan 11 months, 4 weeks ago

    CBSE > Class 12 > Physics
    • 5 answers

    D Chahal 11 months ago

    When light passes from rarer medium to denser medium it bend towards normal..... Or. ...... It can also be termed that when light passes from denser to rarer medium it bends away from its normal , this phenomenon is called refraction.

    0Thank You

    Ankit Singh 11 months, 3 weeks ago

    Because due to medium change , speed of light decreases and it goes to denser medium and hence light bend

    0Thank You

    Abhishek Babu 11 months, 4 weeks ago

    Because of refraction

    0Thank You

    Prashant Singh 11 months, 4 weeks ago

    Light pass from one medium to another is bouncing of light

    0Thank You

    Account Deleted 11 months, 4 weeks ago

    Refraction.

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    ANSWER

    • Posted by Anmol Sharma 1 year ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Shobhit Dixit 1 year ago

    CBSE > Class 12 > Physics
    • 1 answers

    Shobhit Dixit 1 year ago

    A quantity which can be measured and expressed in the form of law is called a physical quantity.

    2Thank You

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    • Posted by Anjali Singh 1 year ago

    CBSE > Class 12 > Physics
    • 2 answers

    Shobhit Dixit 11 months, 4 weeks ago

    Thanks

    5Thank You

    Rahul Kumar 11 months, 4 weeks ago

    20

    4Thank You

    ANSWER

    • Posted by Sadika Parveen 1 year ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Mayank Sharma 1 year ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Puspendu Patel 1 year ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Angel Maria 1 year ago

    CBSE > Class 12 > Physics
    • 3 answers

    D Chahal 11 months ago

    Valence band is the place where all the electrons are exist

    0Thank You

    Xxxxxxxx Xxxxxx 11 months, 1 week ago

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    Diya Bhaneriya 1 year ago

    Bond between conductor and insulators

    4Thank You

    ANSWER
    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    Posted by Kriti Singh 1 year ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Tarannum Ahmad 1 year ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER
    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    Posted by Shivam Chaudhary 1 year ago

    CBSE > Class 12 > Physics
    • 0 answers
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    • Posted by Suraj Singh Meena Meena 1 year ago

    CBSE > Class 12 > Physics
    • 0 answers
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    • Posted by Rekha Sharma 1 year ago

    CBSE > Class 12 > Physics
    • 2 answers

    Xxxxxxxx Xxxxxx 11 months, 1 week ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    0Thank You

    Xxxxxxxx Xxxxxx 11 months, 1 week ago

    12

    0Thank You

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    • Posted by Mohit Tanwar 1 year ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Goutam Singh Chouhan 1 year ago

    CBSE > Class 12 > Physics
    • 3 answers

    Priyanshu Singh 1 year ago

    Munot upon 4pis idl sintetaupon r square

    1Thank You

    Manish Yadav 1 year ago

    Idlsintheta by r square

    0Thank You

    Krish Agrawal 1 year ago

    dB = (μ₀ / 4π) * (Idl × r) / r³

    4Thank You

    ANSWER

    • Posted by Ekta Singla 1 year ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Suraj Negi 1 year, 1 month ago

    CBSE > Class 12 > Physics
    • 1 answers

    Krish Agrawal 1 year ago

    Ernest Rutherford's atomic model, also known as the Rutherford model, was proposed in the early 20th century. It is primarily based on two key postulates: 1. **The Nucleus**: Rutherford postulated that an atom consists of a tiny, dense, and positively charged core at its center, known as the nucleus. This nucleus contains most of the atom's mass and is where the positively charged protons are located. Electrons orbit around the nucleus. 2. **Electron Orbits**: Rutherford proposed that electrons orbit the nucleus in well-defined, circular or elliptical paths. These orbits are sometimes referred to as electron shells or energy levels. Electrons in different shells have different energy levels, and they can jump from one energy level to another by absorbing or emitting energy in the form of electromagnetic radiation. Rutherford's model was groundbreaking because it replaced the earlier Thomson model, which depicted atoms as a "plum pudding" with electrons distributed throughout a positively charged sphere. Rutherford's experiments, most notably the famous gold foil experiment, provided evidence for the existence of the atomic nucleus and laid the foundation for our modern understanding of atomic structure. However, Rutherford's model had limitations and was eventually refined by Niels Bohr and others to account for the quantization of energy levels in electrons and the behavior of atoms in more detail.

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    • Posted by Gangana Pandey 1 year, 1 month ago

    CBSE > Class 12 > Physics
    • 1 answers

    Krish Agrawal 1 year ago

    To calculate the currents in the primary and secondary of a transformer, you can use the transformer equation, which relates the primary and secondary voltages and currents. The equation is: (Vp / Vs) = (Np / Ns) Where: - Vp is the primary voltage. - Vs is the secondary voltage. - Np is the number of turns in the primary coil. - Ns is the number of turns in the secondary coil. In your case, you have: - Np = 500 - Ns = 10 Now, let's calculate the primary voltage (Vp) and the secondary voltage (Vs). The primary voltage (Vp) is typically the voltage applied to the primary coil. To find it, you would need more information, such as the source voltage. Assuming you have the primary voltage (Vp), you can use the equation to find the secondary voltage (Vs): (Vp / Vs) = (Np / Ns) Vs = Vp * (Ns / Np) Now, we need to calculate the currents in the primary and secondary. Use Ohm's Law: I = V / R Where: - I is the current. - V is the voltage. - R is the resistance. For the secondary: - Vs is the voltage (which you've found). - The resistive load is 15 Ω. Isolate the secondary current (Is) and calculate it: Is = Vs / Rs Is = Vs / 15 Ω For the primary current (Ip), you can use the transformer equation again: (Vp / Vs) = (Np / Ns) Ip = Is * (Ns / Np) Substitute the values you have to calculate Ip. Please note that to get precise values, you would need the primary voltage (Vp). Without that information, you won't be able to calculate the exact currents in the primary and secondary coils.

    0Thank You

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    • Posted by Tushar Dulloo 1 year, 1 month ago

    CBSE > Class 12 > Physics
    • 1 answers

    Krish Agrawal 1 year ago

    The sign conventions for the radii of curvature (R1 and R2) for lenses are as follows: 1. **Convex Lens (Diverging Lens)**: - R1 (the radius of curvature of the first surface) is considered positive if the center of curvature is on the same side as the incident light (opposite to the direction of incoming light). - R2 (the radius of curvature of the second surface) is considered negative. 2. **Concave Lens (Converging Lens)**: - R1 (the radius of curvature of the first surface) is considered negative. - R2 (the radius of curvature of the second surface) is considered positive if the center of curvature is on the same side as the incident light (opposite to the direction of incoming light). These conventions are used in lens formula and mirror formula calculations to determine the sign of focal lengths and object distances.

    0Thank You

    ANSWER
    Question 1: A lens has a refractive index of 1.5 and a radius of curvature of 15 cm for one surface and 20 cm for the other surface. Calculate the difference in curvature between the two surfaces using the lens maker's formula Question 2: A concave lens with a refractive index of 1.4 is required to have a focal length of -12 cm. Determine the radil of curvature for the two lens surfaces using the lens maker's formula. Question 3: A biconvex lens with a refractive index of 1.6 has a known focal length of 25 cm. Calculate the difference in radii of curvature for its two surfaces using the lens maker's formula. Question 4 (Easy): A plano-concave lens has a refractive index of 1.2. The radius of curvature of the curved surface is 18 cm, and the flat side has a radius of curvature of infinity, Calculate the focal length of the lens using the lens maker's formula. Question 5 (Easy): A converging lens has a refractive index of 1.6. The radius of curvature of one surface is 12 om, and the radius of curvature of the other surface is 15 cm. Calculate the focal length of the lens using the lens maker's formula.

    • Posted by Tushar Dulloo 1 year, 1 month ago

    CBSE > Class 12 > Physics
    • 1 answers

    Krish Agrawal 1 year ago

    To answer each of your questions, we can use the lens maker's formula, which is given by: \[ \frac{1}{f} = (n - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right) \] Where: - \( f \) is the focal length of the lens. - \( n \) is the refractive index of the material. - \( R_1 \) is the radius of curvature of the first surface. - \( R_2 \) is the radius of curvature of the second surface. Let's solve each of your questions: **Question 1:** Given \( n = 1.5 \), \( R_1 = 15 \, \text{cm} \), and \( R_2 = 20 \, \text{cm} \), we need to calculate the difference in curvature between the two surfaces. Using the lens maker's formula, we can calculate the focal length, and then the difference in curvature. 1. Calculate \( \frac{1}{f} \) using the formula with the given values. 2. Once you find \( \frac{1}{f} \), calculate the focal length \( f \) by taking the reciprocal. **Question 2:** Given \( n = 1.4 \) and \( f = -12 \, \text{cm} \), we need to determine the radii of curvature for the two lens surfaces. Using the lens maker's formula, you can calculate \( R_1 \) and \( R_2 \). 1. Rearrange the lens maker's formula to solve for either \( R_1 \) or \( R_2 \). 2. Plug in the known values and solve for \( R_1 \) and \( R_2 \). **Question 3:** Given \( n = 1.6 \) and \( f = 25 \, \text{cm} \), we need to calculate the difference in radii of curvature for its two surfaces. Again, use the lens maker's formula to calculate \( R_1 \) and \( R_2 \). **Question 4:** Given \( n = 1.2 \), \( R_1 = 18 \, \text{cm} \), and \( R_2 = \infty \) for a flat side, calculate the focal length using the lens maker's formula. **Question 5:** Given \( n = 1.6 \), \( R_1 = 12 \, \text{cm} \), and \( R_2 = 15 \, \text{cm} \), calculate the focal length using the lens maker's formula. For each question, perform the calculations as described above, and you will have the answers you need. If you have any specific values to calculate or encounter any issues, feel free to ask for further assistance.

    0Thank You

    ANSWER

    • Posted by Patcharu Sandeep 1 year, 1 month ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Gaurav Choudhary 1 year, 1 month ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Anshika Saxena 1 year, 1 month ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Haleema Khatoon 1 year, 1 month ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Sunil Prajapat 1 year, 1 month ago

    CBSE > Class 12 > Physics
    • 2 answers

    Ankit Singh 1 year, 1 month ago

    64° approx

    1Thank You

    Gaurav Prabhakar 1 year, 1 month ago

    Pta nahi

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    • Posted by Yuvraj Singh 1 year, 1 month ago

    CBSE > Class 12 > Physics
    • 4 answers

    Krish Agrawal 1 year ago

    100cm

    0Thank You

    Rahul Chauhan 1 year, 1 month ago

    100 cm

    0Thank You

    Faizan Raja 1 year, 1 month ago

    1M=100cm

    0Thank You

    Sunil Prajapat 1 year, 1 month ago

    100 cm

    4Thank You

    ANSWER

    • Posted by Soni Kushwaha 1 year, 1 month ago

    CBSE > Class 12 > Physics
    • 2 answers

    Krish Agrawal 1 year ago

    The power of a combination of two concave lenses can be determined using the lens formula and the power formula for lenses. When lenses are in contact (i.e., their curved surfaces are facing each other), the formula to calculate their combined power is: \[ P_{\text{total}} = P_1 + P_2 \] Where: - \( P_{\text{total}} \) is the total power of the combination of lenses. - \( P_1 \) is the power of the first lens. - \( P_2 \) is the power of the second lens. The power \( P \) of a lens is given by: \[ P = \frac{1}{f} \] Where: - \( P \) is the power of the lens. - \( f \) is the focal length of the lens. If you have two concave lenses with focal lengths \( f_1 \) and \( f_2 \), you can calculate their individual powers as \( P_1 = \frac{1}{f_1} \) and \( P_2 = \frac{1}{f_2} \), respectively. Then, you can find the total power by adding these individual powers. So, to calculate the total power of a combination of two concave lenses, simply add their individual powers using the formula \( P_{\text{total}} = P_1 + P_2 \). This is applicable when the lenses are in contact. If they are separated by a distance, you would need to consider the separation between the lenses when calculating their combined power.

    1Thank You

    Rahul Chauhan 1 year, 1 month ago

    1/f1+1/f2=1/F

    2Thank You

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