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    • Posted by Tarannum Ahmad 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 0 answers
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    • Posted by Suraj Singh Meena Meena 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 0 answers
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    • Posted by Rekha Sharma 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 2 answers

    Xxxxxxxx Xxxxxx 1 year, 9 months ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    0Thank You

    Xxxxxxxx Xxxxxx 1 year, 10 months ago

    12

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    • Posted by Mohit Tanwar 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 0 answers
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    • Posted by Goutam Singh Chouhan 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 3 answers

    Priyanshu Singh 1 year, 10 months ago

    Munot upon 4pis idl sintetaupon r square

    1Thank You

    Manish Yadav 1 year, 11 months ago

    Idlsintheta by r square

    0Thank You

    Krish Agrawal 1 year, 11 months ago

    dB = (μ₀ / 4π) * (Idl × r) / r³

    4Thank You

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    • Posted by Ekta Singla 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 0 answers
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    • Posted by Suraj Negi 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Krish Agrawal 1 year, 11 months ago

    Ernest Rutherford's atomic model, also known as the Rutherford model, was proposed in the early 20th century. It is primarily based on two key postulates: 1. **The Nucleus**: Rutherford postulated that an atom consists of a tiny, dense, and positively charged core at its center, known as the nucleus. This nucleus contains most of the atom's mass and is where the positively charged protons are located. Electrons orbit around the nucleus. 2. **Electron Orbits**: Rutherford proposed that electrons orbit the nucleus in well-defined, circular or elliptical paths. These orbits are sometimes referred to as electron shells or energy levels. Electrons in different shells have different energy levels, and they can jump from one energy level to another by absorbing or emitting energy in the form of electromagnetic radiation. Rutherford's model was groundbreaking because it replaced the earlier Thomson model, which depicted atoms as a "plum pudding" with electrons distributed throughout a positively charged sphere. Rutherford's experiments, most notably the famous gold foil experiment, provided evidence for the existence of the atomic nucleus and laid the foundation for our modern understanding of atomic structure. However, Rutherford's model had limitations and was eventually refined by Niels Bohr and others to account for the quantization of energy levels in electrons and the behavior of atoms in more detail.

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    • Posted by Gangana Pandey 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Krish Agrawal 1 year, 11 months ago

    To calculate the currents in the primary and secondary of a transformer, you can use the transformer equation, which relates the primary and secondary voltages and currents. The equation is: (Vp / Vs) = (Np / Ns) Where: - Vp is the primary voltage. - Vs is the secondary voltage. - Np is the number of turns in the primary coil. - Ns is the number of turns in the secondary coil. In your case, you have: - Np = 500 - Ns = 10 Now, let's calculate the primary voltage (Vp) and the secondary voltage (Vs). The primary voltage (Vp) is typically the voltage applied to the primary coil. To find it, you would need more information, such as the source voltage. Assuming you have the primary voltage (Vp), you can use the equation to find the secondary voltage (Vs): (Vp / Vs) = (Np / Ns) Vs = Vp * (Ns / Np) Now, we need to calculate the currents in the primary and secondary. Use Ohm's Law: I = V / R Where: - I is the current. - V is the voltage. - R is the resistance. For the secondary: - Vs is the voltage (which you've found). - The resistive load is 15 Ω. Isolate the secondary current (Is) and calculate it: Is = Vs / Rs Is = Vs / 15 Ω For the primary current (Ip), you can use the transformer equation again: (Vp / Vs) = (Np / Ns) Ip = Is * (Ns / Np) Substitute the values you have to calculate Ip. Please note that to get precise values, you would need the primary voltage (Vp). Without that information, you won't be able to calculate the exact currents in the primary and secondary coils.

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    • Posted by Tushar Dulloo 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Krish Agrawal 1 year, 11 months ago

    The sign conventions for the radii of curvature (R1 and R2) for lenses are as follows: 1. **Convex Lens (Diverging Lens)**: - R1 (the radius of curvature of the first surface) is considered positive if the center of curvature is on the same side as the incident light (opposite to the direction of incoming light). - R2 (the radius of curvature of the second surface) is considered negative. 2. **Concave Lens (Converging Lens)**: - R1 (the radius of curvature of the first surface) is considered negative. - R2 (the radius of curvature of the second surface) is considered positive if the center of curvature is on the same side as the incident light (opposite to the direction of incoming light). These conventions are used in lens formula and mirror formula calculations to determine the sign of focal lengths and object distances.

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    Question 1: A lens has a refractive index of 1.5 and a radius of curvature of 15 cm for one surface and 20 cm for the other surface. Calculate the difference in curvature between the two surfaces using the lens maker's formula Question 2: A concave lens with a refractive index of 1.4 is required to have a focal length of -12 cm. Determine the radil of curvature for the two lens surfaces using the lens maker's formula. Question 3: A biconvex lens with a refractive index of 1.6 has a known focal length of 25 cm. Calculate the difference in radii of curvature for its two surfaces using the lens maker's formula. Question 4 (Easy): A plano-concave lens has a refractive index of 1.2. The radius of curvature of the curved surface is 18 cm, and the flat side has a radius of curvature of infinity, Calculate the focal length of the lens using the lens maker's formula. Question 5 (Easy): A converging lens has a refractive index of 1.6. The radius of curvature of one surface is 12 om, and the radius of curvature of the other surface is 15 cm. Calculate the focal length of the lens using the lens maker's formula.

    • Posted by Tushar Dulloo 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 1 answers

    Krish Agrawal 1 year, 11 months ago

    To answer each of your questions, we can use the lens maker's formula, which is given by: \[ \frac{1}{f} = (n - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right) \] Where: - \( f \) is the focal length of the lens. - \( n \) is the refractive index of the material. - \( R_1 \) is the radius of curvature of the first surface. - \( R_2 \) is the radius of curvature of the second surface. Let's solve each of your questions: **Question 1:** Given \( n = 1.5 \), \( R_1 = 15 \, \text{cm} \), and \( R_2 = 20 \, \text{cm} \), we need to calculate the difference in curvature between the two surfaces. Using the lens maker's formula, we can calculate the focal length, and then the difference in curvature. 1. Calculate \( \frac{1}{f} \) using the formula with the given values. 2. Once you find \( \frac{1}{f} \), calculate the focal length \( f \) by taking the reciprocal. **Question 2:** Given \( n = 1.4 \) and \( f = -12 \, \text{cm} \), we need to determine the radii of curvature for the two lens surfaces. Using the lens maker's formula, you can calculate \( R_1 \) and \( R_2 \). 1. Rearrange the lens maker's formula to solve for either \( R_1 \) or \( R_2 \). 2. Plug in the known values and solve for \( R_1 \) and \( R_2 \). **Question 3:** Given \( n = 1.6 \) and \( f = 25 \, \text{cm} \), we need to calculate the difference in radii of curvature for its two surfaces. Again, use the lens maker's formula to calculate \( R_1 \) and \( R_2 \). **Question 4:** Given \( n = 1.2 \), \( R_1 = 18 \, \text{cm} \), and \( R_2 = \infty \) for a flat side, calculate the focal length using the lens maker's formula. **Question 5:** Given \( n = 1.6 \), \( R_1 = 12 \, \text{cm} \), and \( R_2 = 15 \, \text{cm} \), calculate the focal length using the lens maker's formula. For each question, perform the calculations as described above, and you will have the answers you need. If you have any specific values to calculate or encounter any issues, feel free to ask for further assistance.

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    • Posted by Patcharu Sandeep 1 year, 11 months ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Gaurav Choudhary 2 years ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Anshika Saxena 2 years ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Haleema Khatoon 2 years ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Sunil Prajapat 2 years ago

    CBSE > Class 12 > Physics
    • 2 answers

    Ankit Singh 1 year, 11 months ago

    64° approx

    1Thank You

    Gaurav Prabhakar 2 years ago

    Pta nahi

    1Thank You

    ANSWER

    • Posted by Yuvraj Singh 2 years ago

    CBSE > Class 12 > Physics
    • 4 answers

    Krish Agrawal 1 year, 11 months ago

    100cm

    0Thank You

    Rahul Chauhan 1 year, 11 months ago

    100 cm

    0Thank You

    Faizan Raja 2 years ago

    1M=100cm

    0Thank You

    Sunil Prajapat 2 years ago

    100 cm

    4Thank You

    ANSWER

    • Posted by Soni Kushwaha 2 years ago

    CBSE > Class 12 > Physics
    • 2 answers

    Krish Agrawal 1 year, 11 months ago

    The power of a combination of two concave lenses can be determined using the lens formula and the power formula for lenses. When lenses are in contact (i.e., their curved surfaces are facing each other), the formula to calculate their combined power is: \[ P_{\text{total}} = P_1 + P_2 \] Where: - \( P_{\text{total}} \) is the total power of the combination of lenses. - \( P_1 \) is the power of the first lens. - \( P_2 \) is the power of the second lens. The power \( P \) of a lens is given by: \[ P = \frac{1}{f} \] Where: - \( P \) is the power of the lens. - \( f \) is the focal length of the lens. If you have two concave lenses with focal lengths \( f_1 \) and \( f_2 \), you can calculate their individual powers as \( P_1 = \frac{1}{f_1} \) and \( P_2 = \frac{1}{f_2} \), respectively. Then, you can find the total power by adding these individual powers. So, to calculate the total power of a combination of two concave lenses, simply add their individual powers using the formula \( P_{\text{total}} = P_1 + P_2 \). This is applicable when the lenses are in contact. If they are separated by a distance, you would need to consider the separation between the lenses when calculating their combined power.

    1Thank You

    Rahul Chauhan 1 year, 11 months ago

    1/f1+1/f2=1/F

    2Thank You

    ANSWER

    • Posted by Komal Sharma 2 years ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Srashti Singh 2 years ago

    CBSE > Class 12 > Physics
    • 1 answers

    Ankur Thenua 2 years ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    1Thank You

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    • Posted by Sharla Maibam 2 years ago

    CBSE > Class 12 > Physics
    • 0 answers
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    • Posted by Aditya Tiwari 2 years ago

    CBSE > Class 12 > Physics
    • 0 answers
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    • Posted by Mj Gamer 2 years ago

    CBSE > Class 12 > Physics
    • 4 answers

    Harshpreet Kaur Sidhu 1 year, 11 months ago

    Volt

    0Thank You

    Harshpreet Kaur Sidhu 1 year, 11 months ago

    Maxwell

    1Thank You

    Kushank Bansal 2 years ago

    Volt

    0Thank You

    • ȺʏꪊSʜ • 2 years ago

    Voltage

    0Thank You

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    • Posted by Ansh Yadav 2 years ago

    CBSE > Class 12 > Physics
    • 1 answers

    Harshpreet Kaur Sidhu 1 year, 11 months ago

    Generator

    0Thank You

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    • Posted by Nitul Bro 2 years ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Kartik Antil 2 years ago

    CBSE > Class 12 > Physics
    • 1 answers

    Sameer Ahmad 2 years ago

    What is electric field

    3Thank You

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    • Posted by Steeva Anna Raju 2 years ago

    CBSE > Class 12 > Physics
    • 1 answers

    Broker Jaat 2 years ago

    N =300

    0Thank You

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    • Posted by Neeraj Gujjar 2 years ago

    CBSE > Class 12 > Physics
    • 3 answers

    Aryan Rana 2 years ago

    Coil moveing in area

    1Thank You

    Aryan Rana 2 years ago

    Sir

    2Thank You

    Aryan Rana 2 years ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    • Posted by Nancy Lidiyaa 2 years ago

    CBSE > Class 12 > Physics
    • 4 answers

    Aseem Mahajan 2 years ago

    <font face ="Times New Roman">DIY the proving part
    Work done is 0 (intuitively too)
    If field was not uniform, the dipole will experience a net force with torque.

    1Thank You

    Shalini Shalini 2 years ago

    Zero

    0Thank You

    Neeraj Gujjar 2 years ago

    Zero

    1Thank You

    Sankalp Yadav 2 years ago

    Zero

    1Thank You

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    • Posted by Priyanshi Rana 2 years ago

    CBSE > Class 12 > Physics
    • 0 answers
    ANSWER

    • Posted by Lise Dahila 2 years ago

    CBSE > Class 12 > Physics
    • 0 answers
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