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The force that q exert on 2q is given by Coulomb's law:
- F = k (q) ( - 2q) / r²,
- r = 0.5 m,
- F = - 0.20 N,
- 0.2 = - 2 q² k / 0.52
q² = 0.2 × 0.52 / (2k)
q = √ [(0.2 × 0.52 / (2 × 9 × 109)]
= 1.66 × 10^-6 C
q = 1.66 × 10^-6 C,
-2 q = -3.23 × 10^-6 C
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Vishal M 4 years, 5 months ago
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