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  • 3 answers

Yogita Ingle 6 years, 5 months ago

Coloumb’s law has the following three limitations:

  • The charges should be point charges i.e the charges are placed at a point which have no dimensions
  • The second limitation is the distance between the two charges remains constant.
  • The third limitation of Coloumb’s law is that the charges should not radiate any amount of energy. For eg in Bohr’s postulate, Coloumb’s law is applicable to the electron moving around the nucleus as it is assumed that the electron does not radiate any energy.

Tapur Dhiman 6 years, 5 months ago

It is only applicable for charges which are at rest and it is only applicable for point charge

Sunidhi Asthana 6 years, 5 months ago

1.It applicable only point charges. 2.charges should be of same sign. 3.charges should present at rest.
  • 1 answers

Kritika Dhingra 6 years, 5 months ago

Its Q=ne
  • 1 answers

Avaneesh Tiwari 6 years, 5 months ago

Yes
  • 1 answers

Sunidhi Asthana 6 years, 5 months ago

Electric field in dipole all three cases. Gauss's three applications are most important.
  • 2 answers

Yogita Ingle 6 years, 5 months ago

The ability of an capacitor to store the energy in form of electric charge is known as Capacitance.

In other words capacitance can be described as the storing ability of a capacitor and it is measured in farads.

For Example, if we connected a capacitor to a 9 volt battery and measured that it stored 9 coulombs of charge, its capacitance would be 1 farad

Akhilesh Urmaliya 6 years, 5 months ago

Property of material of condensor Charge storing capacity with out change in shape or size
  • 1 answers

Evvi Mishra 6 years, 5 months ago

V = k Q / r
  • 1 answers

Sunidhi Asthana 6 years, 5 months ago

Because it is equipotential surface where potential is same everywhere W=qv,here both charge and potential are same therefore work doesn't matter over whatever be path..
  • 1 answers

Ayushi Ayushi 6 years, 5 months ago

1. 1/4¥€0 q1×q2/r^2 2. E=F/q0 3. E =1/4¥€0 q/r^2 4. p=2lq Due to dipole moment - 5. E=1/4¥€0 2p / l^3 ( on the axis ) 6. E =1/4¥€0 p/l^3 ( in broad side on position )
  • 3 answers

Rahul Gupta 6 years, 5 months ago

It will form a cuboid of dimensions 10x20x10 When you draw the diagram. Then calculate its diagonal length Using the formula =sum of squares of Length breadth and height Then calculate the root it is final answer. 24.5 is the answer

Amarjot Singh 6 years, 5 months ago

40

Manika Gupta 6 years, 5 months ago

A rt anglef triangle is obt when u draw figure then using phythagorous theorem u can find displacement
  • 1 answers

Shatayu Ganvir 6 years, 5 months ago

To jake bacha na bichareko
  • 3 answers

Priya Dharshini ? 6 years, 5 months ago

Not yet decided about it mid of september u will come to know about it
1 to 10 will be mcqs nd 11 to 20 one word.

Aman Kumar 6 years, 5 months ago

I think both......not cleared
  • 1 answers

Yogita Ingle 6 years, 5 months ago

Law of Malus : According to Malus, when completely plane polarised light is incident on the analyser, the intensity I of the light transmitted by the analyser is directly proportional to the square of the cosine of angle between the transmission axes of the analyser and polarizer i.e I{tex} \alpha co{{s}^{2}} \theta {/tex}.

  • 6 answers

Priya Dharshini ? 6 years, 5 months ago

Ya wat aman said is correct..... many books are there once u need to check which book u r able to understand. If u r weak in numericals of physics choose the book which is having more numericals

Aman Kumar 6 years, 5 months ago

Bro....For chemistry :- Modern ABC, Comprehensive, pradeep .....For physics:- S.L Arora, pradeep.........but friend if possible.. ek baar apne se jarur check kar lena...ki tumhe kon se book ke concepts aur numerical simple lag rahe hai.....waise bhi book lene toh tumhi jaoge....so u can check that

Ɽøⱨł₮ ₲Ʉ₱₮₳ 6 years, 5 months ago

For chemistry modern's abc+
everyone have different opinion according to their understanding... kisi ko kuch se smjh aata hai kisi ko kuch se but ager tum puch re ho toh Chemistry ke liye Modern best hai aur kuch pradeep bolenge... but Arihant is common... so Arihant +NCERT +modern ya pradeep... now for physics ncert +SL ya hcv + IRODOV. but kahne per mt chalna Jo thik lage vahi use kerna... rest gud luck... ✌️

Priya Dharshini ? 6 years, 5 months ago

For Chemistry arihant or examidea is best for boards for competitive exams op tandon,p bagadur ,physics- sl arora,hc verma then for maths rd sharma or rs agarwal...

Vijayan Cp 6 years, 5 months ago

Bhai exam idea best hai
  • 4 answers

Aaditya Rathore??? 6 years, 5 months ago

Darshana new id

Simmi Sharma 6 years, 5 months ago

It is an imaginary line which describe the direction of electric field. It may be curve or straight. It orginated from positive charge and terminated at negative charge. It don't form close loop

Harsh Pahuja 6 years, 5 months ago

Electric field lines are imaginary lines which tells the direction of the field lines (i.e from +ve to -ve) for isolated -ve charge it moves from infinity to the space near the charge and vice-versa for +ve charge.
These are the imaginary lines ⚞ which shows the direction of electric field around the source charge.
  • 3 answers

Aman Kumar 6 years, 5 months ago

Fie = Charged enclosed/ €not.... =>Charged enclosed/€not = E A cos theta
✴️ The flux of electric field through any closed surface S is 1/ε0 times the total charge enclosed by S. ✴️ Electric field outside the charged shell is as though the total charge is concentrated at the centre. The same result is true for a solid sphere of uniform volume charge density. ✴️ The electric field is zero at all points inside a charged shell

Raman Raman 6 years, 5 months ago

The electric flux link with any surface is always equal to 1/e0 times
  • 2 answers

Nishu Sahu 6 years, 5 months ago

It tell about additivity of charges. Q1 and Q2 are equal and opposite charges.

Me Souhardee❤️ 6 years, 5 months ago

It tells that the charges are attractive in nature as Q1=-Q2, ?
  • 1 answers

Simmi Sharma 6 years, 5 months ago

Q= 20×20×10^-6× 10^-6c.... permittivity =4 r=40cm=0.4m. F=9×10^9×20×20×10^-6×10-6÷0.4×0.4 = 3600×10^9-12÷0.4×0.4 3600×10-3/0.4×0.4 3600×10-3 3.6.

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