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Lavanya ❤️? 6 years, 5 months ago

In chemistry solid states
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Prakhar Dubey 6 years, 5 months ago

Bernoulli theorem Doppler effect torricelli law Teminal velocity
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Simran Kalra 6 years, 5 months ago

Coulomb's law in vector form , electric field of a dipole at equitorial and axial point , torque ob a dipole , all applications of GAUSS'S theorem

Akshay Meena 6 years, 5 months ago

Gauss law and Columbus's low

Lily ☺ 6 years, 5 months ago

Applications of gauss law

Mandavi Tripathi 6 years, 5 months ago

All derivation is important for the purpose of board exam
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Nishu Sahu 6 years, 5 months ago

Communication system
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Yogita Ingle 6 years, 5 months ago

Attraction may occur between two oppositely charged bodies or a charged body and an uncharged one. That is why in attraction, one is not sure if both bodies are charged, However in repulsion, there are two bodies that have the same charge. That is why repulsion is the sure test of electrification.

Read more on Brainly.in - https://brainly.in/question/1756095#readmore

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Div¥@N$Hi P@M@® 6 years, 5 months ago

E=1/2pie£° *lemda/r
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Simran Kalra 6 years, 5 months ago

Yeah!
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Samruddhi Dundage 6 years, 5 months ago

Now the force will be 3/8times of F This is bcoz initially force was kq^2/r^2. Now on touching c to a charges on c and a will be q/2 .when thus q/2charge on c is again touched with B then the charge on b will be 3/4 q . Now the final force will be k q^2 /r^2 ×3/8.thus it is 3/8times that if initial force
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Gaurav Seth 6 years, 5 months ago

Electric Field Intensity:

Electric field intensity is the measure of intensity or strength of electrical force per unit charge at any given point in the electric field. It is denoted by the letter and its Unit is Newton per Coulomb (N/C).

Mathematically we can derive the expression or formula for the Electric field intensity as:

As shown in the figure below:

Let, Q1 and Q2 be the two charges separated by a distance “d” and let F be the force built between them.

Now, If we need to calculate the electric field intensity in Q2 due to the electric field of Q1 then by definition the electric field intensity is the electrical force per unit charge.
Or,

And by Coulomb's law, we know the force F =

Thus,

Or,

  • 1 answers

Aman Singh 6 years, 5 months ago

The electric flux is defined as the electric field passing through a given area multiplied by the area of the surface in a plane perpendicular to the field. Another statement of Gauss's law is that the net flux of an electric field through a surface divided by the enclosed charge is equal to a constant. The surface that we choose for application of Gauss' theorem is called Gaussian surface. We usually choose a spherical Gaussian surface

  1. Electric field due to a long straight wire of sheet
  2. Electric field due to a plane sheet of charge
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Lily ☺ 6 years, 5 months ago

S l arora

Ajay Kumar 6 years, 5 months ago

Pardeep

Shreyansh Rawat 6 years, 5 months ago

If talking about numerical portion- *pradeep* wolud be the best book for it.?

Navyansh Kumar 6 years, 5 months ago

Pradeep

Samruddhi Dundage 6 years, 5 months ago

H c verma

Someone ?? 6 years, 5 months ago

Pradeep's
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Yogita Ingle 6 years, 5 months ago

The divergence of electric field through a surface is equal to the charge enclosed in that surface (Gauss Law).
Thus clearly if they would have formed closed loop, the divergence would have been always zero irrespective of the charge enclosed, like that in case of magnetic lines of force.

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Yogita Ingle 6 years, 5 months ago

Electric Flux is defined as a number of electric field lines, passing per unit area. It is another physical quantity to measure the strength of electric field and frame the basics of electrostatics. It is also defined as the product of electric field and surface area projected in a direction perpendicular to the electric field. Let’s understand what the term flux actually means, with an example.

Example:

Suppose there a liquid flowing with velocity ‘v’, through tiny surface dS, in a normal direction with respect to the surface. The rate of flow of water will be volume passing through the area per unit time that is v dS.

Volume = Area × Length

Differentiating the above relation with respect to time, we get

d Volume/ dt = dS × d length/ dt

Flow of liquid = dS × v 

where dS is a surface area perpendicular to the velocity v of water, and v is the velocity of liquid (rate of change of length per unit time)

This flow of liquid, that is the quantity v dS, is called flux. If there is some angle θ between the velocity of liquid and surface area dS and flux of liquid, can be evaluated from the relation:

Flow of liquid = v dS cos θ

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